On Sun, 15 Jun 2008 19:01:13 +0000 (UTC), rambotrout
<rambotrout@[EMAIL PROTECTED]
> wrote:
>Please correct me if I am wrong.
>
>Say the voltage across the slabs is Vt, then Vt = V1 + V2, where V1,
>V2 are voltages across the two different dielectric materials.
>Therefore,
>
>Vt = Q*d1/(E1 * A) + Q*d2/(E2 * A),
>
>where Q = charge in Coulomb, d = thickness of material, E = dielectric
>constant, and A = area.
That's right. Vt = Q/C1 + Q/C2
where E is K*eps0, where K is a multiplier of vacuum permittivity.
John Polasek
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