On Mon, 16 Jun 2008 17:03:49 -0700, "N:dlzc D:aol T:com \(dlzc\)"
<dlzc1@[EMAIL PROTECTED]
> wrote:
>Dear rambotrout:
>
>"rambotrout" <rambotrout@[EMAIL PROTECTED]
> wrote in message
>news:20ed4345-0da2-47d2-942c-ce21db760ae4@[EMAIL PROTECTED]
>> Thank you everyone for all the replies.
>>
>> I have better grasp of it now.
>>
>> Timo, if the electrode is thinly insulated, wouldn't
>> all the ions get attracted very close to their
>> respective electrodes thus leaving the water
>> "relatively" pure?
>
>Yes. "Electrodeionization".
>
>> In this case, wouldn't the dielectric
>> constant of the water is retained?
>
>Yes, as I gave you numbers before:
>pure water, k = 80
>salt water, k = 81
>
>David A. Smith
The water might break down under fairly weak fields because K = 80 is
a very high number for a simple natural substance. What this means is
that the bound electrons are on very weak "springs" and have large
deflections (K = 80) so that a moderate field might break the springs
and free the electron for conduction.
If the battery remains connected, the E field is still there,
exacerbated by local ionizations, and able to do more ionization
rather than herding ions where they can't do any harm.
What is "thinly insulated"?
John Polasek
John Polasek
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