Camilo wrote:
> let me see if I understood you. Amperage of the HV source acts as a
> source of electrons (or lack of them when it´s a positive field ) so
> for that reason is im****tant amperage on the ionization process
> performance, ¿ Am I right?
> But anyway, taking up again the previous example ¿what happen with
> Ionization if I have by A case a HV source with 100 Kvolts and by B
> case the same 10Kvolts, both with 1000 watts of output?
In an ionizer, the corona discharge (that generates the ions) will draw
a current that is function of the applied voltage. Once the applied
voltage is sufficient to generate a corona discharge, the current drawn
by a ionizer will be the same for a given applied voltage no matter if
you have a 10 watt supply or a 1000 watt supply. However, if you
increase the applied voltage to the same ionizer, the corona current
will increase very nonlinearly. Doubling the voltage will cause the
corona current to increase by significantly more than 2X. Assuming your
ionizer does not flash over at 100 kV, the current and power drawn from
the HV supply could be 100X larger (or more). Your results will vary as
a function of the ambient gas pressure, gas mixture, applied electrical
polarity (if DC), waveshape and frequency (if AC or pulsed), and the
geometry of your ionizer.
Bert
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