On Tue, 01 Jul 2008 21:40:52 GMT, "Bill Miller"
<billmillerkt4ye@[EMAIL PROTECTED]
> wrote:
>
>"John C. Polasek" <jpolasek@[EMAIL PROTECTED]
> wrote in message
>news:4g0l64p0qplifdsjh9eusjvbgja1kdgtvq@[EMAIL PROTECTED]
>> On Tue, 01 Jul 2008 17:28:17 GMT, "Bill Miller"
>> <billmillerkt4ye@[EMAIL PROTECTED]
> wrote:
>>
>>>
>>>"John C. Polasek" <jpolasek@[EMAIL PROTECTED]
> wrote in message
>>>news:olsi64dpq3djae7k2p3qk1nb92ja7da625@[EMAIL PROTECTED]
>> ruthless snip
>>>>>
>>>>>Even in introductory texts, it wouldn't be terribly difficult to say
>>>>>something like, "Maxwell's equations demonstrate a clear relation****p
>>>>>between Electric(E) and Magnetic (H) fields. This is sometimes
>>>>>erroneously
>>>>>interpreted as meaning that E causes H and H causes E. However, a
>>>>>careful
>>>>>analysis shows that E fields and H fields are sololy caused by
charges
>>>>>and
>>>>>the movement of charges.""
>>>>>
>>>>>Not too hard.
>>>> You are full of beans.
>>>
>>>Yep... Had some last night.
>>>
>>>As soon as the currents pulse up and down in
>>>> the antenna, a good ****tion of the energy exits as EM waves that take
>>>> off across the country. They're on their own and don't need overt
>>>> charges or currents. E, D, B and H are taken care of by polarization
>>>> of eps0 and mu0, properties of the vacuum. They exchange energies as
>>>> they go along.
>>>
>>>Your case would be stronger if E and H (in an EM wave) were out of
phase.
>>>Then we would have a situation analagous to -- say -- a spring or water
>>>waves, wherein kinetic energy gets swapped for potential energy, etc.
>>>
>>>BUT E and H are in phase! How in the world can anyone imagine that two
in
>>>phase and contiguaous signals are *swapping* energy? If you can do so,
I
>>>believe we would all love to hear how it works.
>>
>> OK, here's how they swap energy, (and remember, you promised to love
>> to hear this).
>> Using spring mass for simplicity
>
>I just dropped everything, rushed outside and looked at my antennas. No
>matter how hard I looked, I couldn't find a spring.
>
>>and recognizing that the wave will be
>> sinusoidal, the force on the spring is pro****tional to displacement
>> Fk = F0 sin wt (say)
>> The force on the mass is pro****tional to acceleration, two derivatives
>> removed, so it's 180 degrees out of phase.
>> Fm = - w^2F0 sin wt
>> The energies likewise peak 180 degrees apart.
>>
>
>I'm sorry, John. I still don' see no spring!
You have not looked at my model of the ether (pairspace) on my
website. The springs are right in front of your nose; capacitive
energy is stored in the extension of the springs: dx = E*e/K.
It is the only arrangement that will duplicate the action of eps0.
The spring/mass resonance for the bound charges in space is
w = sqrt(K/m) = 1.693e22 rad/sec.
The frequency response of any radiation frequency f or w, fits on a
Bode diagram, showing the mass has very little effect till we approach
resonance:
Kx = mW^2x
Fm/Fk = w^2/W^2
>And while Saint Albert (and the bomb) taught us that Energy and Mass have
>equivalency, I do not see where mass enters into this situation.
>
>Are you perhaps suggesting that the free space epsilon exhibits the same
>type of spring-like latency that we see in the epsilon of many solid
>dielectrics? If so, then, yes, we see a phase ****ft.
Of course I am. See the website. It all works.
>But I am not aware of any such phase ****ft that has bee measured in free
>space. If this is your suggestion, then show us the free space
experimental
>evidence, please.
>
>> So you were approximately correct, that they are in phase, yes, in a
>> larger sense. After all, what's a minus sign? Well, shucks, let's just
>> admit that they are out of phase, as you were opining, making my case
>> stronger as you point out. I'm gratified.
>>
>>>THEN stand by your phone for the Stockholm call!
>>>
>>>> Your assumption of currents and charges being present and essential
is
>>>> just as valid as the teams now looking for Wimps and Machos to
explain
>>>> the dark matter problem.
>>>
>>>Currents and charges are essential to LAUNCH the wave(s). Afterwards,
the
>>>separate E and H signals are in lock step and isolated.
>>>
>>>> By the way which do you prefer:
>>>> D = E and B = H
>>>> or D = eps0E and B = mu0H ?
>>>
>>>I pick....
>>>
>>>Let's see...
>>>
Clearly it would be fruitless for me to go through a whole lot of
handsprings for someone who still thinks the vacuum is empty and D=E
and B=H, equations that are easy to memorize, but which, even with a
little more substance added, barely approach tautology.
Maxwell's Ddot lives!
>>>
>>>Oh gosh, I just can't decide!
>>
>> You dodged the D=E bullet. That's a sure sign of a benighted cgs'er
>> who at least has the decency to feel a little guilty.
>
>OK You caught me! I choose...
>
>British Thermal Units and Furlongs Per Fortnight
>
>Bill
>
>>
>>>>>Bill
John Polasek
http://www.dualspace.net
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