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Science > Electromagnetics > How does a Fara...
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How does a Faraday disk really work?

by Salmon Egg <SalmonEgg@[EMAIL PROTECTED] > Aug 1, 2008 at 05:41 PM

After all these these years dealing with electromagnetism, I still do 
not fully understand a Faraday disk based upon Maxwell's equations. To 
be specific let me describe a particular configuration.

1.  There is a uniform magnetic field in the vertical direction 
extending over the region that will contain all the apparatus.

2.  The axle mounting a circular disk is vertical so that the disk is in 
the horizontal plane. This axis and disk, both of conducting material is 
what spins.

3.  To make electrical connection, there is a conducting circular 
cylindrical skirt attached the disk's periphery. This skirt dips into a 
circular trough containing mercury. A similar but smaller skirt and 
trough arrangement is used to connect to the axle shaft. Connections to 
measure what happens are made to the trough bodies. These wires are not 
moved during the testing.

4.  These wires are connected to a variable dc source through a 
galvanometer. When running, the source is adjusted so that the current 
flow is zero. By using this potentiometric technique, there will be no 
current to confuse what is happening. Maxwell's equations will also be 
simplified.

Maxwell's equations for this case are:

div B = 0.             Always true anyway.

div D = 0.             There is no free charge. There is the possible     

-                      exception at the disk edge and the like, but I do 
-                      not think this charge is significant.

curl E = 0.            There is no time variation of the magnetic field.

curl H = 0.            There is no conducted or displacement current.

When the disk turns, how do you explain the potential difference 
measured by the external potentiometer?

Something has to be added to the Maxwell equations. For example, I think 
that you have to add an equation representing the definition of the 
electric field. Charge is a concept that is not explicitly defined but 
which can be measured in terms of forces between charges. Given a charge 
of size q, the electrical field is determined by F = q E once the 
mechanical force is measured. Once you know and measure charge, you know 
what current is.

I think that the other thing that needs to be known is equivalent to 
knowing how the electromagnetic tensor in 4-space transforms with 
motion. that is, relativistically, when a point moves through a magnetic 
field, it sees an electric field introduced by the motion at the point.

This electric field may be called the Lorentz force or something 
similar, but it seems to be something that must be added to  the 
equations I have already listed. This arises simply out of relativity 
where the EM field has to be a tensor and has to transform properly with 
a Lorentz transformation.

Questions:

1.  Can this Lorentz force be derived without invoking relativity or 
another law of nature? That is, are Maxwell's equations sufficient?

2.  Given Maxwell's equations and F = q E, can the forces between wires 
carrying current be derived?
 




 10 Posts in Topic:
How does a Faraday disk really work?
Salmon Egg <SalmonEgg@  2008-08-01 17:41:43 
Re: How does a Faraday disk really work?
Benj <bjacoby@[EMAIL P  2008-08-02 08:59:24 
Re: How does a Faraday disk really work?
Salmon Egg <SalmonEgg@  2008-08-02 12:12:01 
Re: How does a Faraday disk really work?
"Timo A. Nieminen&qu  2008-08-03 08:28:59 
Re: How does a Faraday disk really work?
"Timo A. Nieminen&qu  2008-08-03 08:55:20 
Re: How does a Faraday disk really work?
Benj <bjacoby@[EMAIL P  2008-08-03 00:58:26 
Re: How does a Faraday disk really work?
blackhead <larryharson  2008-08-06 16:34:57 
Re: How does a Faraday disk really work?
Salmon Egg <SalmonEgg@  2008-08-06 22:23:19 
Re: How does a Faraday disk really work?
blackhead <larryharson  2008-08-07 05:54:16 
Re: How does a Faraday disk really work?
Benj <bjacoby@[EMAIL P  2008-08-07 21:48:41 

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tan12V112 Fri Sep 5 21:45:48 CDT 2008.