Re: Induction: Aetherists lend me a hand!

On Aug 9, 10:39=A0am, blackhead <larryhar...@[EMAIL PROTECTED]
> wrote:
> On 8 Aug, 23:02, Benj <bjac...@[EMAIL PROTECTED]
> wrote:

> Since E is, by definition, the force per unit charge that increases
> its kinetic energy, then I don't see how creating a name for E when
> the charge is static and another for when it is moving helps. They are
> both the same - A measurement of the force on a charge that increases
> its kinetic energy. Perhaps by "Electrokinetic E" you mean the E that
> arises from the complex interaction of the sources and responses
> propagating with a finite velocity C which is too complicated to model
> fundamentally.
>
> > For everyone else: We are talking here about placing a charge on on
> > pole of an electromagnet that is increasing (or decreasing) in field.
> > The charge will experience a force that drives it in a circle. BUT the
> > direction and location of the circle depend upon the initial velocity
> > of the charge! There is NOT a single E field in a single direction!

Yes the effect of an E field is to increase the kinetic energy of the
charge so they are ALL "E" fields. The question is are they all the
SAME E field?  Bridgeman proposed that one should examine these things
in an "operational" approach.  namely to note how the given "E" field
arises. For example. A static E field arises from the Position of the
charges. A qVxB  field from the Velocity (first derivative of
position) of the charges and the Inductive E field from the
Acceleration of the charges (second derivative).  He therefore
suggested that these should be treated as separate things.

Since "ElectroKinetic E field" is not my terminology, I can't say why
the name was chosen, but the E field produced by induction has
properties that are NOTHING like an electrostatic E field. Hence it
would be a true stretch to say they are the "same".  As I noted in the
example above, the latter depends upon the initial velocity a charge
has, while the former does not. But you are right they both provide
momentum transfer to a charge and thus both are "E" fields in that
sense.